6(y^2+5)-3(2y^2+1)+y=28

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Solution for 6(y^2+5)-3(2y^2+1)+y=28 equation:


Simplifying
6(y2 + 5) + -3(2y2 + 1) + y = 28

Reorder the terms:
6(5 + y2) + -3(2y2 + 1) + y = 28
(5 * 6 + y2 * 6) + -3(2y2 + 1) + y = 28
(30 + 6y2) + -3(2y2 + 1) + y = 28

Reorder the terms:
30 + 6y2 + -3(1 + 2y2) + y = 28
30 + 6y2 + (1 * -3 + 2y2 * -3) + y = 28
30 + 6y2 + (-3 + -6y2) + y = 28

Reorder the terms:
30 + -3 + y + 6y2 + -6y2 = 28

Combine like terms: 30 + -3 = 27
27 + y + 6y2 + -6y2 = 28

Combine like terms: 6y2 + -6y2 = 0
27 + y + 0 = 28
27 + y = 28

Solving
27 + y = 28

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-27' to each side of the equation.
27 + -27 + y = 28 + -27

Combine like terms: 27 + -27 = 0
0 + y = 28 + -27
y = 28 + -27

Combine like terms: 28 + -27 = 1
y = 1

Simplifying
y = 1

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